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Hal Jameson @_e_e_e_e_e_e_e_@dolphin.town
(̅_̅_̅(̲̲̲̲̲̅̅̅̅̅̅(̅_̅_̲̅ e _̅_̅_̅()ڪے
e <=> e
(e^E)' = e^E-1
e² = e² + e²
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